If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2z^2-3z-14=0
a = 2; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·2·(-14)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-11}{2*2}=\frac{-8}{4} =-2 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+11}{2*2}=\frac{14}{4} =3+1/2 $
| 3y2+7y-6=0 | | 6x2-29x+20=0 | | 15+.50m=25+25m | | 3w2+49w+60=0 | | v2-5v-24=0 | | u2+6u-27=0 | | r2-16r+63=0 | | s(s+6)=48 | | s2+10s+21=0 | | 4q2-12q+9=0 | | y/20=70 | | 25p2+70p+49=0 | | m2-16m+64=0 | | k2+12k+36=0 | | -4h2-16h=0 | | 3f-81f2=0 | | 3d2-4d=0 | | 5c2+25c=0 | | a2+9a=0 | | 12(n-3)=4(n+1 | | 3x+2+0=3x+2+1 | | (5s+3)(2-s)=0 | | -12v-7+9v=26 | | (p+1)(p+2)=0 | | w-4/3+5=6 | | n^2-5n-300=0 | | 4(t-8)=3+6+2 | | 4(t-8)=6+2 | | -7(4x+5)=30 | | 3x+2x+1=5 | | s(s+12)=21 | | 20x^2+48x-19=0 |