3((-18+10y)/5)-6y=-20

Solution for 3((-18+10y)/5)-6y=-20 equation:

3((-18+10y)/5)-6y=-20

We move all terms to the left:

3((-18+10y)/5)-6y-(-20)=0

We add all the numbers together, and all the variables

3((10y-18)/5)-6y-(-20)=0

We add all the numbers together, and all the variables

-6y+3((10y-18)/5)+20=0

We multiply all the terms by the denominator


-6y*5)+3((10y-18)+20*5)=0

We add all the numbers together, and all the variables

-6y*5)+3((10y-18)=0

Wy multiply elements

-30y^2=0

a = -30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-30)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-60}=0$