3((-2y+5)/5)-4y=29

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Solution for 3((-2y+5)/5)-4y=29 equation: 



3((-2y+5)/5)-4y=29

We move all terms to the left:

3((-2y+5)/5)-4y-(29)=0

We add all the numbers together, and all the variables

-4y+3((-2y+5)/5)-29=0

We multiply all the terms by the denominator


-4y*5)+3((-2y+5)-29*5)=0

We add all the numbers together, and all the variables

-4y*5)+3((-2y+5)=0

Wy multiply elements

-20y^2=0

a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-40}=0$

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