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3((2)/(3)x-10)=(-12)
We move all terms to the left:
3((2)/(3)x-10)-((-12))=0
Domain of the equation: 3x-10)!=0We add all the numbers together, and all the variables
x∈R
3(2/3x-10)+12=0
We multiply parentheses
6x-30+12=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3
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