3((2j/3)-6)=32

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Solution for 3((2j/3)-6)=32 equation: 



3((2j/3)-6)=32

We move all terms to the left:

3((2j/3)-6)-(32)=0

We add all the numbers together, and all the variables

3((+2j/3)-6)-32=0

We multiply all the terms by the denominator


3((+2j-32*3)-6)=0

We add all the numbers together, and all the variables

3((2j-96)-6)=0

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