3((2x+5)-10)+2x+5+x=42

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Solution for 3((2x+5)-10)+2x+5+x=42 equation: 



3((2x+5)-10)+2x+5+x=42

We move all terms to the left:

3((2x+5)-10)+2x+5+x-(42)=0

We add all the numbers together, and all the variables

3x+3((2x+5)-10)-37=0

We move all terms containing x to the left, all other terms to the right

3x+3((2x+5)-10)=37

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