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3((30-9y)/8)+8y=6
We move all terms to the left:
3((30-9y)/8)+8y-(6)=0
We add all the numbers together, and all the variables
3((-9y+30)/8)+8y-6=0
We add all the numbers together, and all the variables
8y+3((-9y+30)/8)-6=0
We multiply all the terms by the denominator
8y*8)+3((-9y+30)-6*8)=0
We add all the numbers together, and all the variables
8y*8)+3((-9y+30)=0
Wy multiply elements
64y^2=0
a = 64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·64·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{128}=0$
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