3((5+4x)/(1-3x))+4

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Solution for 3((5+4x)/(1-3x))+4 equation: 


D( x )

1-(3*x) = 0

1-(3*x) = 0

1-(3*x) = 0

1-3*x = 0

1-3*x = 0 // - 1

-3*x = -1 // : -3

x = -1/(-3)

x = 1/3

x in (-oo:1/3) U (1/3:+oo)

3*((4*x+5)/(1-(3*x)))+4 = 0

3*((4*x+5)/(1-3*x))+4 = 0

(3*(4*x+5))/(1-3*x)+4 = 0

(3*(4*x+5))/(1-3*x)+(4*(1-3*x))/(1-3*x) = 0

3*(4*x+5)+4*(1-3*x) = 0

19 = 0

19/(1-3*x) = 0

19/(1-3*x) = 0 // * 1-3*x

19 = 0

x belongs to the empty set

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