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3((x+2)/2)-2((x+3)/5)+x-1=13x/10+1
We move all terms to the left:
3((x+2)/2)-2((x+3)/5)+x-1-(13x/10+1)=0
We add all the numbers together, and all the variables
x+3((x+2)/2)-2((x+3)/5)-(13x/10+1)-1=0
We get rid of parentheses
x+3((x+2)/2)-2((x+3)/5)-13x/10-1-1=0
We calculate fractions
We do not support expression: x^3
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