3(+2)-j=2(j=1)

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Solution for 3(+2)-j=2(j=1) equation: 



3(+2)-j=2(j=1)

We move all terms to the left:

3(+2)-j-(2(j)=0

We add all the numbers together, and all the variables

-j-(2j+32=0

We add all the numbers together, and all the variables

-1j-(2j+32=0

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