3(-1-2r)+3r=5r-7(6+r)

Solution for 3(-1-2r)+3r=5r-7(6+r) equation:

3(-1-2r)+3r=5r-7(6+r)

We move all terms to the left:

3(-1-2r)+3r-(5r-7(6+r))=0

We add all the numbers together, and all the variables

3(-2r-1)+3r-(5r-7(r+6))=0

We add all the numbers together, and all the variables

3r+3(-2r-1)-(5r-7(r+6))=0

We multiply parentheses

3r-6r-(5r-7(r+6))-3=0


We calculate terms in parentheses: -(5r-7(r+6)), so:

5r-7(r+6)

We multiply parentheses

5r-7r-42

We add all the numbers together, and all the variables

-2r-42

Back to the equation:

-(-2r-42)


We add all the numbers together, and all the variables

-3r-(-2r-42)-3=0

We get rid of parentheses

-3r+2r+42-3=0

We add all the numbers together, and all the variables

-1r+39=0

We move all terms containing r to the left, all other terms to the right

-r=-39

r=-39/-1

r=+39