3(-15-8c)=3(-10c-24)

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Solution for 3(-15-8c)=3(-10c-24) equation: 



3(-15-8c)=3(-10c-24)

We move all terms to the left:

3(-15-8c)-(3(-10c-24))=0

We add all the numbers together, and all the variables

3(-8c-15)-(3(-10c-24))=0

We multiply parentheses

-24c-(3(-10c-24))-45=0



We calculate terms in parentheses: -(3(-10c-24)), so:

3(-10c-24)

We multiply parentheses

-30c-72

Back to the equation:

-(-30c-72)



We get rid of parentheses

-24c+30c+72-45=0

We add all the numbers together, and all the variables

6c+27=0

We move all terms containing c to the left, all other terms to the right

6c=-27

c=-27/6

c=-4+1/2

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