3(-2/3)y+2y=0

Solution for 3(-2/3)y+2y=0 equation:

3(-2/3)y+2y=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

2y+3(-2/3)y=0

We multiply parentheses

-6y^2+2y=0

a = -6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-6}=\frac{-4}{-12}
=1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-6}=\frac{0}{-12}
=0
$