3(-20x-3)+11=15(-4x+2)-28

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Solution for 3(-20x-3)+11=15(-4x+2)-28 equation: 



3(-20x-3)+11=15(-4x+2)-28

We move all terms to the left:

3(-20x-3)+11-(15(-4x+2)-28)=0

We multiply parentheses

-60x-(15(-4x+2)-28)-9+11=0



We calculate terms in parentheses: -(15(-4x+2)-28), so:

15(-4x+2)-28

We multiply parentheses

-60x+30-28

We add all the numbers together, and all the variables

-60x+2

Back to the equation:

-(-60x+2)



We add all the numbers together, and all the variables

-60x-(-60x+2)+2=0

We get rid of parentheses

-60x+60x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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