3(-22-2k)=6(1+3k)

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Solution for 3(-22-2k)=6(1+3k) equation: 



3(-22-2k)=6(1+3k)

We move all terms to the left:

3(-22-2k)-(6(1+3k))=0

We add all the numbers together, and all the variables

3(-2k-22)-(6(3k+1))=0

We multiply parentheses

-6k-(6(3k+1))-66=0



We calculate terms in parentheses: -(6(3k+1)), so:

6(3k+1)

We multiply parentheses

18k+6

Back to the equation:

-(18k+6)



We get rid of parentheses

-6k-18k-6-66=0

We add all the numbers together, and all the variables

-24k-72=0

We move all terms containing k to the left, all other terms to the right

-24k=72

k=72/-24

k=-3

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