3(-2b+3)=3-3b

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Solution for 3(-2b+3)=3-3b equation: 



3(-2b+3)=3-3b

We move all terms to the left:

3(-2b+3)-(3-3b)=0

We add all the numbers together, and all the variables

3(-2b+3)-(-3b+3)=0

We multiply parentheses

-6b-(-3b+3)+9=0

We get rid of parentheses

-6b+3b-3+9=0

We add all the numbers together, and all the variables

-3b+6=0

We move all terms containing b to the left, all other terms to the right

-3b=-6

b=-6/-3

b=+2

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