3(-2x+1)=3x-4(2-x)

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Solution for 3(-2x+1)=3x-4(2-x) equation: 



3(-2x+1)=3x-4(2-x)

We move all terms to the left:

3(-2x+1)-(3x-4(2-x))=0

We add all the numbers together, and all the variables

3(-2x+1)-(3x-4(-1x+2))=0

We multiply parentheses

-6x-(3x-4(-1x+2))+3=0



We calculate terms in parentheses: -(3x-4(-1x+2)), so:

3x-4(-1x+2)

We multiply parentheses

3x+4x-8

We add all the numbers together, and all the variables

7x-8

Back to the equation:

-(7x-8)



We get rid of parentheses

-6x-7x+8+3=0

We add all the numbers together, and all the variables

-13x+11=0

We move all terms containing x to the left, all other terms to the right

-13x=-11

x=-11/-13

x=11/13

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