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3(-2x+1)=5-2(x+1)
We move all terms to the left:
3(-2x+1)-(5-2(x+1))=0
We multiply parentheses
-6x-(5-2(x+1))+3=0
We calculate terms in parentheses: -(5-2(x+1)), so:We get rid of parentheses
5-2(x+1)
determiningTheFunctionDomain -2(x+1)+5
We multiply parentheses
-2x-2+5
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
-6x+2x-3+3=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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