3(-2y+4)+1=2(3y+1)+15

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Solution for 3(-2y+4)+1=2(3y+1)+15 equation: 



3(-2y+4)+1=2(3y+1)+15

We move all terms to the left:

3(-2y+4)+1-(2(3y+1)+15)=0

We multiply parentheses

-6y-(2(3y+1)+15)+12+1=0



We calculate terms in parentheses: -(2(3y+1)+15), so:

2(3y+1)+15

We multiply parentheses

6y+2+15

We add all the numbers together, and all the variables

6y+17

Back to the equation:

-(6y+17)



We add all the numbers together, and all the variables

-6y-(6y+17)+13=0

We get rid of parentheses

-6y-6y-17+13=0

We add all the numbers together, and all the variables

-12y-4=0

We move all terms containing y to the left, all other terms to the right

-12y=4

y=4/-12

y=-1/3

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