3(-2z+1)=4z+13

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Solution for 3(-2z+1)=4z+13 equation: 



3(-2z+1)=4z+13

We move all terms to the left:

3(-2z+1)-(4z+13)=0

We multiply parentheses

-6z-(4z+13)+3=0

We get rid of parentheses

-6z-4z-13+3=0

We add all the numbers together, and all the variables

-10z-10=0

We move all terms containing z to the left, all other terms to the right

-10z=10

z=10/-10

z=-1

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