3(-3)+6=3(2t-5)

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Solution for 3(-3)+6=3(2t-5) equation: 



3(-3)+6=3(2t-5)

We move all terms to the left:

3(-3)+6-(3(2t-5))=0

We add all the numbers together, and all the variables

-(3(2t-5))-3=0



We calculate terms in parentheses: -(3(2t-5)), so:

3(2t-5)

We multiply parentheses

6t-15

Back to the equation:

-(6t-15)



We get rid of parentheses

-6t+15-3=0

We add all the numbers together, and all the variables

-6t+12=0

We move all terms containing t to the left, all other terms to the right

-6t=-12

t=-12/-6

t=+2

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