3(-3+9d)=2(9+9d)

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Solution for 3(-3+9d)=2(9+9d) equation: 



3(-3+9d)=2(9+9d)

We move all terms to the left:

3(-3+9d)-(2(9+9d))=0

We add all the numbers together, and all the variables

3(9d-3)-(2(9d+9))=0

We multiply parentheses

27d-(2(9d+9))-9=0



We calculate terms in parentheses: -(2(9d+9)), so:

2(9d+9)

We multiply parentheses

18d+18

Back to the equation:

-(18d+18)



We get rid of parentheses

27d-18d-18-9=0

We add all the numbers together, and all the variables

9d-27=0

We move all terms containing d to the left, all other terms to the right

9d=27

d=27/9

d=3

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