3(-3+x)=2(-6+3x)

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Solution for 3(-3+x)=2(-6+3x) equation: 



3(-3+x)=2(-6+3x)

We move all terms to the left:

3(-3+x)-(2(-6+3x))=0

We add all the numbers together, and all the variables

3(x-3)-(2(3x-6))=0

We multiply parentheses

3x-(2(3x-6))-9=0



We calculate terms in parentheses: -(2(3x-6)), so:

2(3x-6)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

3x-6x+12-9=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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