3(-3-3b)-5(3-3b)=0

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Solution for 3(-3-3b)-5(3-3b)=0 equation: 



3(-3-3b)-5(3-3b)=0

We add all the numbers together, and all the variables

3(-3b-3)-5(-3b+3)=0

We multiply parentheses

-9b+15b-9-15=0

We add all the numbers together, and all the variables

6b-24=0

We move all terms containing b to the left, all other terms to the right

6b=24

b=24/6

b=4

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