3(-3b-2)=-33

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Solution for 3(-3b-2)=-33 equation: 



3(-3b-2)=-33

We move all terms to the left:

3(-3b-2)-(-33)=0

We add all the numbers together, and all the variables

3(-3b-2)+33=0

We multiply parentheses

-9b-6+33=0

We add all the numbers together, and all the variables

-9b+27=0

We move all terms containing b to the left, all other terms to the right

-9b=-27

b=-27/-9

b=+3

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