3(-3c+4)=15

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Solution for 3(-3c+4)=15 equation: 



3(-3c+4)=15

We move all terms to the left:

3(-3c+4)-(15)=0

We multiply parentheses

-9c+12-15=0

We add all the numbers together, and all the variables

-9c-3=0

We move all terms containing c to the left, all other terms to the right

-9c=3

c=3/-9

c=-1/3

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