3(-3s-12)+40=24s-41

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Solution for 3(-3s-12)+40=24s-41 equation: 



3(-3s-12)+40=24s-41

We move all terms to the left:

3(-3s-12)+40-(24s-41)=0

We multiply parentheses

-9s-(24s-41)-36+40=0

We get rid of parentheses

-9s-24s+41-36+40=0

We add all the numbers together, and all the variables

-33s+45=0

We move all terms containing s to the left, all other terms to the right

-33s=-45

s=-45/-33

s=1+4/11

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