3(-4+2s)=2(s+2)-4

Solution for 3(-4+2s)=2(s+2)-4 equation:

3(-4+2s)=2(s+2)-4

We move all terms to the left:

3(-4+2s)-(2(s+2)-4)=0

We add all the numbers together, and all the variables

3(2s-4)-(2(s+2)-4)=0

We multiply parentheses

6s-(2(s+2)-4)-12=0


We calculate terms in parentheses: -(2(s+2)-4), so:

2(s+2)-4

We multiply parentheses

2s+4-4

We add all the numbers together, and all the variables

2s

Back to the equation:

-(2s)


We add all the numbers together, and all the variables

4s-12=0

We move all terms containing s to the left, all other terms to the right

4s=12

s=12/4

s=3