3(-4+9c)=2(3+9c)

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Solution for 3(-4+9c)=2(3+9c) equation: 



3(-4+9c)=2(3+9c)

We move all terms to the left:

3(-4+9c)-(2(3+9c))=0

We add all the numbers together, and all the variables

3(9c-4)-(2(9c+3))=0

We multiply parentheses

27c-(2(9c+3))-12=0



We calculate terms in parentheses: -(2(9c+3)), so:

2(9c+3)

We multiply parentheses

18c+6

Back to the equation:

-(18c+6)



We get rid of parentheses

27c-18c-6-12=0

We add all the numbers together, and all the variables

9c-18=0

We move all terms containing c to the left, all other terms to the right

9c=18

c=18/9

c=2

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