3(-4b)+40/2=-4b

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Solution for 3(-4b)+40/2=-4b equation: 



3(-4b)+40/2=-4b

We move all terms to the left:

3(-4b)+40/2-(-4b)=0

We add all the numbers together, and all the variables

3(-4b)-(-4b)+20=0

We multiply parentheses

-12b-(-4b)+20=0

We get rid of parentheses

-12b+4b+20=0

We add all the numbers together, and all the variables

-8b+20=0

We move all terms containing b to the left, all other terms to the right

-8b=-20

b=-20/-8

b=2+1/2

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