3(-4b)-2(a-b-c)=

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Solution for 3(-4b)-2(a-b-c)= equation:


Simplifying
3(-4b) + -2(a + -1b + -1c) = 0

Remove parenthesis around (-4b)
3 * -4b + -2(a + -1b + -1c) = 0

Multiply 3 * -4
-12b + -2(a + -1b + -1c) = 0
-12b + (a * -2 + -1b * -2 + -1c * -2) = 0
-12b + (-2a + 2b + 2c) = 0

Reorder the terms:
-2a + -12b + 2b + 2c = 0

Combine like terms: -12b + 2b = -10b
-2a + -10b + 2c = 0

Solving
-2a + -10b + 2c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '10b' to each side of the equation.
-2a + -10b + 10b + 2c = 0 + 10b

Combine like terms: -10b + 10b = 0
-2a + 0 + 2c = 0 + 10b
-2a + 2c = 0 + 10b
Remove the zero:
-2a + 2c = 10b

Add '-2c' to each side of the equation.
-2a + 2c + -2c = 10b + -2c

Combine like terms: 2c + -2c = 0
-2a + 0 = 10b + -2c
-2a = 10b + -2c

Divide each side by '-2'.
a = -5b + c

Simplifying
a = -5b + c

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