3(-5y+4)=-8y-2+3y-6

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Solution for 3(-5y+4)=-8y-2+3y-6 equation: 



3(-5y+4)=-8y-2+3y-6

We move all terms to the left:

3(-5y+4)-(-8y-2+3y-6)=0

We add all the numbers together, and all the variables

3(-5y+4)-(-5y-8)=0

We multiply parentheses

-15y-(-5y-8)+12=0

We get rid of parentheses

-15y+5y+8+12=0

We add all the numbers together, and all the variables

-10y+20=0

We move all terms containing y to the left, all other terms to the right

-10y=-20

y=-20/-10

y=+2

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