3(-6-2y)=2(2y-3)-2

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Solution for 3(-6-2y)=2(2y-3)-2 equation:



3(-6-2y)=2(2y-3)-2
We move all terms to the left:
3(-6-2y)-(2(2y-3)-2)=0
We add all the numbers together, and all the variables
3(-2y-6)-(2(2y-3)-2)=0
We multiply parentheses
-6y-(2(2y-3)-2)-18=0
We calculate terms in parentheses: -(2(2y-3)-2), so:
2(2y-3)-2
We multiply parentheses
4y-6-2
We add all the numbers together, and all the variables
4y-8
Back to the equation:
-(4y-8)
We get rid of parentheses
-6y-4y+8-18=0
We add all the numbers together, and all the variables
-10y-10=0
We move all terms containing y to the left, all other terms to the right
-10y=10
y=10/-10
y=-1

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