3(-7v-2)=-5(5v-10)+12v

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Solution for 3(-7v-2)=-5(5v-10)+12v equation: 



3(-7v-2)=-5(5v-10)+12v

We move all terms to the left:

3(-7v-2)-(-5(5v-10)+12v)=0

We multiply parentheses

-21v-(-5(5v-10)+12v)-6=0



We calculate terms in parentheses: -(-5(5v-10)+12v), so:

-5(5v-10)+12v

We add all the numbers together, and all the variables

12v-5(5v-10)

We multiply parentheses

12v-25v+50

We add all the numbers together, and all the variables

-13v+50

Back to the equation:

-(-13v+50)



We get rid of parentheses

-21v+13v-50-6=0

We add all the numbers together, and all the variables

-8v-56=0

We move all terms containing v to the left, all other terms to the right

-8v=56

v=56/-8

v=-7

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