3(-c-18)=3c-18

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Solution for 3(-c-18)=3c-18 equation:



3(-c-18)=3c-18
We move all terms to the left:
3(-c-18)-(3c-18)=0
We add all the numbers together, and all the variables
3(-1c-18)-(3c-18)=0
We multiply parentheses
-3c-(3c-18)-54=0
We get rid of parentheses
-3c-3c+18-54=0
We add all the numbers together, and all the variables
-6c-36=0
We move all terms containing c to the left, all other terms to the right
-6c=36
c=36/-6
c=-6

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