3(-x+2)-2(-x+1)=10(-x+2)-21

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Solution for 3(-x+2)-2(-x+1)=10(-x+2)-21 equation: 



3(-x+2)-2(-x+1)=10(-x+2)-21

We move all terms to the left:

3(-x+2)-2(-x+1)-(10(-x+2)-21)=0

We add all the numbers together, and all the variables

3(-1x+2)-2(-1x+1)-(10(-1x+2)-21)=0

We multiply parentheses

-3x+2x-(10(-1x+2)-21)+6-2=0



We calculate terms in parentheses: -(10(-1x+2)-21), so:

10(-1x+2)-21

We multiply parentheses

-10x+20-21

We add all the numbers together, and all the variables

-10x-1

Back to the equation:

-(-10x-1)



We add all the numbers together, and all the variables

-1x-(-10x-1)+4=0

We get rid of parentheses

-1x+10x+1+4=0

We add all the numbers together, and all the variables

9x+5=0

We move all terms containing x to the left, all other terms to the right

9x=-5

x=-5/9

x=-5/9

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