3(-x-5)+55=-4(2x+2)+x

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Solution for 3(-x-5)+55=-4(2x+2)+x equation: 



3(-x-5)+55=-4(2x+2)+x

We move all terms to the left:

3(-x-5)+55-(-4(2x+2)+x)=0

We add all the numbers together, and all the variables

3(-1x-5)-(-4(2x+2)+x)+55=0

We multiply parentheses

-3x-(-4(2x+2)+x)-15+55=0



We calculate terms in parentheses: -(-4(2x+2)+x), so:

-4(2x+2)+x

We add all the numbers together, and all the variables

x-4(2x+2)

We multiply parentheses

x-8x-8

We add all the numbers together, and all the variables

-7x-8

Back to the equation:

-(-7x-8)



We add all the numbers together, and all the variables

-3x-(-7x-8)+40=0

We get rid of parentheses

-3x+7x+8+40=0

We add all the numbers together, and all the variables

4x+48=0

We move all terms containing x to the left, all other terms to the right

4x=-48

x=-48/4

x=-12

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