3(-x2-2)=-(2x-4)+2

Solution for 3(-x2-2)=-(2x-4)+2 equation:

3(-x2-2)=-(2x-4)+2

We move all terms to the left:

3(-x2-2)-(-(2x-4)+2)=0

We add all the numbers together, and all the variables

3(-1x^2-2)-(-(2x-4)+2)=0

We multiply parentheses

-3x^2-(-(2x-4)+2)-6=0


We calculate terms in parentheses: -(-(2x-4)+2), so:

-(2x-4)+2

We get rid of parentheses

-2x+4+2

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)


We get rid of parentheses

-3x^2+2x-6-6=0

We add all the numbers together, and all the variables

-3x^2+2x-12=0

a = -3; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-3)·(-12)
Δ = -140
Delta is less than zero, so there is no solution for the equation