3(-y+3)+y=-3

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Solution for 3(-y+3)+y=-3 equation: 



3(-y+3)+y=-3

We move all terms to the left:

3(-y+3)+y-(-3)=0

We add all the numbers together, and all the variables

3(-1y+3)+y-(-3)=0

We add all the numbers together, and all the variables

y+3(-1y+3)+3=0

We multiply parentheses

y-3y+9+3=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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