3(-y+z+4)+2y+4z=17

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Solution for 3(-y+z+4)+2y+4z=17 equation:


Simplifying
3(-1y + z + 4) + 2y + 4z = 17

Reorder the terms:
3(4 + -1y + z) + 2y + 4z = 17
(4 * 3 + -1y * 3 + z * 3) + 2y + 4z = 17
(12 + -3y + 3z) + 2y + 4z = 17

Reorder the terms:
12 + -3y + 2y + 3z + 4z = 17

Combine like terms: -3y + 2y = -1y
12 + -1y + 3z + 4z = 17

Combine like terms: 3z + 4z = 7z
12 + -1y + 7z = 17

Solving
12 + -1y + 7z = 17

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -1y + -12 + 7z = 17 + -12

Reorder the terms:
12 + -12 + -1y + 7z = 17 + -12

Combine like terms: 12 + -12 = 0
0 + -1y + 7z = 17 + -12
-1y + 7z = 17 + -12

Combine like terms: 17 + -12 = 5
-1y + 7z = 5

Add '-7z' to each side of the equation.
-1y + 7z + -7z = 5 + -7z

Combine like terms: 7z + -7z = 0
-1y + 0 = 5 + -7z
-1y = 5 + -7z

Divide each side by '-1'.
y = -5 + 7z

Simplifying
y = -5 + 7z

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