3(-z+12)=4(z-5)

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Solution for 3(-z+12)=4(z-5) equation:


Simplifying
3(-1z + 12) = 4(z + -5)

Reorder the terms:
3(12 + -1z) = 4(z + -5)
(12 * 3 + -1z * 3) = 4(z + -5)
(36 + -3z) = 4(z + -5)

Reorder the terms:
36 + -3z = 4(-5 + z)
36 + -3z = (-5 * 4 + z * 4)
36 + -3z = (-20 + 4z)

Solving
36 + -3z = -20 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
36 + -3z + -4z = -20 + 4z + -4z

Combine like terms: -3z + -4z = -7z
36 + -7z = -20 + 4z + -4z

Combine like terms: 4z + -4z = 0
36 + -7z = -20 + 0
36 + -7z = -20

Add '-36' to each side of the equation.
36 + -36 + -7z = -20 + -36

Combine like terms: 36 + -36 = 0
0 + -7z = -20 + -36
-7z = -20 + -36

Combine like terms: -20 + -36 = -56
-7z = -56

Divide each side by '-7'.
z = 8

Simplifying
z = 8

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