3(1)=72/f-5

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Solution for 3(1)=72/f-5 equation: 



3(1)=72/f-5

We move all terms to the left:

3(1)-(72/f-5)=0



Domain of the equation: f-5)!=0

f∈R



We get rid of parentheses

-72/f+5+31=0

We multiply all the terms by the denominator


5*f+31*f-72=0

We add all the numbers together, and all the variables

36f-72=0

We move all terms containing f to the left, all other terms to the right

36f=72

f=72/36

f=2

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