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3(1+2a)=4(a+3)-5(2a-3)
We move all terms to the left:
3(1+2a)-(4(a+3)-5(2a-3))=0
We add all the numbers together, and all the variables
3(2a+1)-(4(a+3)-5(2a-3))=0
We multiply parentheses
6a-(4(a+3)-5(2a-3))+3=0
We calculate terms in parentheses: -(4(a+3)-5(2a-3)), so:We get rid of parentheses
4(a+3)-5(2a-3)
We multiply parentheses
4a-10a+12+15
We add all the numbers together, and all the variables
-6a+27
Back to the equation:
-(-6a+27)
6a+6a-27+3=0
We add all the numbers together, and all the variables
12a-24=0
We move all terms containing a to the left, all other terms to the right
12a=24
a=24/12
a=2
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