3(1+2f)=

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Solution for 3(1+2f)= equation: 



3(1+2f)=

We move all terms to the left:

3(1+2f)-()=0

We add all the numbers together, and all the variables

3(2f+1)-()=0

We add all the numbers together, and all the variables

3(2f+1)=0

We multiply parentheses

6f+3=0

We move all terms containing f to the left, all other terms to the right

6f=-3

f=-3/6

f=-1/2

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