3(1+2f)=

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Solution for 3(1+2f)= equation:



3(1+2f)=
We move all terms to the left:
3(1+2f)-()=0
We add all the numbers together, and all the variables
3(2f+1)-()=0
We add all the numbers together, and all the variables
3(2f+1)=0
We multiply parentheses
6f+3=0
We move all terms containing f to the left, all other terms to the right
6f=-3
f=-3/6
f=-1/2

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