3(1+2x)-7(8x-1)=40

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Solution for 3(1+2x)-7(8x-1)=40 equation: 



3(1+2x)-7(8x-1)=40

We move all terms to the left:

3(1+2x)-7(8x-1)-(40)=0

We add all the numbers together, and all the variables

3(2x+1)-7(8x-1)-40=0

We multiply parentheses

6x-56x+3+7-40=0

We add all the numbers together, and all the variables

-50x-30=0

We move all terms containing x to the left, all other terms to the right

-50x=30

x=30/-50

x=-3/5

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