3(1+2y)=y+2(y+2y)

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Solution for 3(1+2y)=y+2(y+2y) equation: 



3(1+2y)=y+2(y+2y)

We move all terms to the left:

3(1+2y)-(y+2(y+2y))=0

We add all the numbers together, and all the variables

3(2y+1)-(y+2(+3y))=0

We multiply parentheses

6y-(y+2(+3y))+3=0



We calculate terms in parentheses: -(y+2(+3y)), so:

y+2(+3y)

We multiply parentheses

y+6y

We add all the numbers together, and all the variables

7y

Back to the equation:

-(7y)



We add all the numbers together, and all the variables

-1y+3=0

We move all terms containing y to the left, all other terms to the right

-y=-3

y=-3/-1

y=+3

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