3(1+3a)+6=4a+34

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Solution for 3(1+3a)+6=4a+34 equation: 



3(1+3a)+6=4a+34

We move all terms to the left:

3(1+3a)+6-(4a+34)=0

We add all the numbers together, and all the variables

3(3a+1)-(4a+34)+6=0

We multiply parentheses

9a-(4a+34)+3+6=0

We get rid of parentheses

9a-4a-34+3+6=0

We add all the numbers together, and all the variables

5a-25=0

We move all terms containing a to the left, all other terms to the right

5a=25

a=25/5

a=5

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