3(1+3a)=6(a+2)

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Solution for 3(1+3a)=6(a+2) equation: 



3(1+3a)=6(a+2)

We move all terms to the left:

3(1+3a)-(6(a+2))=0

We add all the numbers together, and all the variables

3(3a+1)-(6(a+2))=0

We multiply parentheses

9a-(6(a+2))+3=0



We calculate terms in parentheses: -(6(a+2)), so:

6(a+2)

We multiply parentheses

6a+12

Back to the equation:

-(6a+12)



We get rid of parentheses

9a-6a-12+3=0

We add all the numbers together, and all the variables

3a-9=0

We move all terms containing a to the left, all other terms to the right

3a=9

a=9/3

a=3

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