3(1+4)+7r=3(1-8r)

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Solution for 3(1+4)+7r=3(1-8r) equation: 



3(1+4)+7r=3(1-8r)

We move all terms to the left:

3(1+4)+7r-(3(1-8r))=0

We add all the numbers together, and all the variables

7r-(3(-8r+1))+35=0



We calculate terms in parentheses: -(3(-8r+1)), so:

3(-8r+1)

We multiply parentheses

-24r+3

Back to the equation:

-(-24r+3)



We get rid of parentheses

7r+24r-3+35=0

We add all the numbers together, and all the variables

31r+32=0

We move all terms containing r to the left, all other terms to the right

31r=-32

r=-32/31

r=-1+1/31

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