3(1+4c)=25

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Solution for 3(1+4c)=25 equation: 



3(1+4c)=25

We move all terms to the left:

3(1+4c)-(25)=0

We add all the numbers together, and all the variables

3(4c+1)-25=0

We multiply parentheses

12c+3-25=0

We add all the numbers together, and all the variables

12c-22=0

We move all terms containing c to the left, all other terms to the right

12c=22

c=22/12

c=1+5/6

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